举一反三
- 【单选题】下面 C代码的输出结果是()。int answer,result;answer=100;result=answer-10;printf( “The result is %d” , result+5); A. The result is 90 B. The result is 95 C. The result is 10 D. The result is 100
- 下面程序的运行结果是( )。 #include<iostream.h> int fun(int a[],int n) int result=1; for(int i=1;i<n;i++) result=result *a[i]; return result; void main() int a[3]=3,4,5; eout<<fun(a,3)<<end1;[/i] A: 12 B: 15 C: 20 D: 60
- 下面程序段的输出结果是( )。 public class Test public static void main ( String[] args) int result=0; for ( int i=1;i<=5;i++) if ( i%2==0 ) continue; result + =i; System. out. println ("result is " + result ); A: result is 7 B: result is 8 C: result is 9 D: result is 10
- 下面程序段的输出结果是( )。 public class Test public static void main (String[] args) int n=10,result=0; for (int i=1;i<=n;i++) result+=i; System.out.println("result is"+result); A: A) result is 55 B: B) result is 45 C: C) result is 56 D: D) result is 54
- 以下代码的运行结果为 def calculate(number): result = 0 i = 1 while i <= number: result = result + i i += 1 return result result = calculate(100) print('1~100的累积和为:', result)
内容
- 0
下面的方法,当输入为2的时候返回值是多少?( ) public static int getValue(int i) { int result = 0; switch (i) { case 1: result = result + i; case 2: result = result + i * 2; case 3: result = result + i * 3; } return result; }
- 1
输出9*9乘法表,补充完整以下程序。 #include void main() { int i,j,result; printf(" "); for (i=1;____①____;i++) { for(j=1;____②____;j++) { result=i*j; printf("%d*%d=%-3d",i,j,result); } printf(" "); } }
- 2
下面的方法,当参数值为2的时候返回值是多少public int getValue(int i) { int result = 0; switch (i) { case 1: result = result + i; case 2: result = result + i * 2; case 3: result = result + i * 3; } return result; } A: 10 B: 8 C: 6 D: 4 E: 2 F: 0
- 3
以下代码执行的结果是:( )int i=2;int result = 0;switch (i) {case 1:result = result + i;case 2:result = result + i * 2;case 3:result = result + i * 3;}System.out.println(result); A: 0 B: 2 C: 4 D: 10
- 4
6. #include "stdio.h" void main( ) {int k , result=0; for(k=1;k<=6;k++) result+=k*k; } 程序中 result 结果为 ______