• 2022-06-27
    用户输入0-100之间的百分制成绩,将其转为五分制输出,下面正确的答案为:
    A: score = float(input()) degree = "EEEEEEDCBAA" score_five = degree[score / 10] print(score_five)
    B: score = float(input()) degree = "EEEEEEDCBAA" score_five = degree[score // 10] print(score_five)
    C: score = float(input()) degree = "EEEEEEDCBAA" score_five = degree[int(score // 10)] print(score_five)
    D: score = float(input()) degree = "EEEEEEDCBA" score_five = degree[int(score // 10)] print(score_five)
  • C

    内容

    • 0

      下面代码的输出结果是()。 <?php $score=87; if($score>=90 && $score<=100){$grade="优秀";} if($score>=80){$grade="良好";} if($score>=70){$grade="一般";} if($score>=60){$grade="及格";} else{$grade="不及格";} echo $grade; ?>

    • 1

      定义一个存储5个学生成绩的数组不正确的是() A: int[] score = new int[5]; B: int score[] = new int[5]; C: double[] score; score = new double[5]; D: double[] score = new double[];

    • 2

      从学生成绩表SC中查询平均成绩大于60分的同学的学号和平均成绩的正确语句为: A: selectsno,avg(score)assscorefromscgroupbysnohavingavg(score)>60 B: selectsno,avg(score)assscorefromscgroupbysnowhereavg(score)>60 C: selectsno,avg(score)assscorefromscwhereavg(score)>60 D: selectsno,avg(score)assscorefromschavingavg(score)>60

    • 3

      查询成绩在60-80之间的学生信息,正确的语句是? A: db.students.find({"score":{$gte:60,$lte:80}}) B: db.students.find({"score":{$gte:80},{"score":{$lte:60}}}) C: db.students.find({"score":{$gte:60},{"score":{$te:80}}}) D: db.students.find({"score":{$gt:80},{"score":{$lt:60}}})

    • 4

      下列结构体中定义正确的是 A: record{<br/>int no;<br/>char num[16];<br/>float score;<br/>} B: struct record{<br/>int no;<br/>char num[16];<br/>float score;<br/>} C: struct record{<br/>int no;<br/>char num[16];<br/>float score;<br/>}; D: struct record{<br/>int no<br/>char num[16]<br/>float score<br/>};