用定义判断广义积分[tex=6.286x2.714]qN8fOJEmxCPwE8y3sw7ScxLLeZ0uFYPXDWTxrmtch5kKWtXDdOyvdNuWqZH3WkkM[/tex][tex=5.214x1.286]3yUyW8Q/6u/QiUYW0N5KGDjVE8I7LMIeDpzuG7EInaY=[/tex]的敛散性，若收敛，则求其值.
举一反三
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 判断下列广义积分敛散性；若收敛，则求其值：[tex=5.786x2.857]D+OdHpWjBNPXoMUoCawgfn9bUS7wATG7lOpbXxWOUZIG8yUI8Fh3Jh2Quqo5CUei[/tex].
- 判断下列广义积分敛散性；若收敛，则求其值：[tex=4.714x2.714]wJGaTThFo41W0bFf87CfUmuQ6To02D15ITMi2ivyMd8=[/tex].
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']