A: Python！
B: python
C: Python
D: python！
举一反三
- 以下程序的输出结果是:ls = [‘book’ , 666 ,[2018,’python’,20 ]print(ls[2][1][-2]) A: n B: python C: o D: 结果错误
- 以下程序的输出结果是:Lis1 = [1,2,[‘python’]]Lis2 =[‘ loves ’]Lis1[ 1 ] = lis2print(lis1) } A: [ lis2 ,2,[ 'python'] ] B: [1,[ 'loves'], [ 'python'] ] C: [1,2, ‘python' ,’loves' ] D: [1 ,2,[ 'python' ,'loves' ]
- 执行以下代码输出的是a = 〃Python〃print(a.upper()) A: PYTHON B: python C: Python D: "Python"
- 如下代码输出结果是 （ ）s = 'Python is Open Source!'print(s[0:].upper()) A: PYTHON IS OPEN SOURCE B: Python is Open Source! C: PYTHON D: PYTHON IS OPEN SOURCE!
- s = 'Python is Open Source!'print(s[0:].upper())上述代码的输出结果是 A: PYTHON IS OPEN SOURCE! B: Python is Open Source! C: PYTHON IS OPEN SOURCE D: PYTHON
内容
- 0
执行以下程序,输出结果是:() st='python'st.upper()print(st) A: PYTHON B: ‘python’ C: ‘PYTHON’ D: python
- 1
给出如下代码s = 'Python is Open Source!'print(s[0:].upper())上述代码的输出结果是( )。 A: PYTHON B: Python is Open Source! C: PYTHON IS OPEN SOURCE! D: PYTHON IS OPEN SOURCE
- 2
给出如下代码:s = 'Python is Open Source!'print(s[0:].upper())上述代码的输出结果是 。 A: PYTHON IS OPEN SOURCE! B: PYTHON IS OPEN SOURCE C: Python is Open Source! D: PYTHON
- 3
以下代码的输出结果是( )。 ls = ["2020", "20.20", "Python"] ls.append([2020, "2020"]) [br][/br]print(ls) A: ['2020', '20.20', 'Python', [2020, '2020']] B: ['2020', '20.20', 'Python', 2020, ['2020']] C: ['2020', '20.20', 'Python', 2020,] D: ['2020', '20.20', 'Python', 2020, '2020']
- 4
语句print("{0:=^20}".format("Python"))输出结果是: ==============Python|=======Python=======|Python|Python==============