2-3 设有如下函数f( t ),试分别画出它们的波形。 (a) f( t ) = 2e( t -1 ) - 2e( t -2 ) (b) f( t ) = sinpt[e( t ) - e( t -6 )]
解 (a)和(b)的波形如图p2-3所示。 图p2-3
举一反三
- 【多选题】若f 1 (t) = ɛ (-t) , f 2 (t) = e t ,则f 1 (t)* f 2 (t) = A. f 1 ꞌ (t)* f 2 (–1) (t) B. f 1 (–1) (t)* f 2 ꞌ (t) C. f 1 (t-3)* f 2 (t+3) D. f 1 (–3) (t)* f 2 ꞌꞌꞌ (t)
- 已知因果函数f (t)的象函数为F (s),则e –3 t f (0.5t–1)的象函数为 A: e–2s F (s+3) B: 2e–2(s+3) F(2s+6) C: 2e–2(s+3)F (s+3) D: 2e–(2s+3)F (2s+3)
- 已知x(t)=[1,0,3]; y(t)=[2,1]; 计算卷积f(t)=x(t)*y(t) A: f(t)=[1,2,3,6] B: f(t)=[2,1,6,3] C: f(t)=[2,0,6] D: f(t)=[3,0,9] E: f(t)=[2,4,1,2]
- 设f(1)=0,t<3,试确定信号f(1-1)+f(2-t)为0的t值 A: t>-2或t>-1 B: t=1或t=2 C: t>-1 D: t>-2
- 若F(ω)=[f(t)],利用Fourier变换的性质求下列函数g(t)的Fourier变换.(1)g(t)=tf(2t);(2)g(t)=(t一2)f(t);(3)g(t)=(t一2)f(一2t);(4)g(t)=t3f(2t);(5)g(t)=tf’(t);(6)g(t)=f(1一t);(7)g(t)=(1一t)f(1一t);(8)g(t)=f(2t一5).
内容
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1-2 给定题1-2图示信号f( t ),试画出下列信号的波形。[提示:f( 2t )表示将f( t )波形压缩,f()表示将f( t )波形展宽。] (a) 2 f( t - 2 ) (b) f( 2t ) (c) f( ) (d) f( -t +1 ) 题1-2图cbbd98684dd083c3d1d5adeb5771a3d5.png13f05861df0e3166b99b987942917b16.jpgcbbd98684dd083c3d1d5adeb5771a3d5.png
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设\(z = {e^{x - 2y}}\),而\(x = \sin t\),\(y = {t^3}\),则全导数\( { { dz} \over {dt}} = \) A: \({e^{\sin t - {t^3}}}(\cos t - 6{t^2})\) B: \({e^{\sin t - 2{t^3}}}(\sin t - 6{t^2})\) C: \({e^{\cos t - 2{t^3}}}(\cos t - 6{t^2})\) D: \({e^{\sin t - 2{t^3}}}(\cos t - 6{t^2})\)
- 2
已知f1(t)和f2(t)波形如下,若f(t)=f1(t)*f2(t),则f(0)= A: 1 B: 2 C: 3 D: 4
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Fill in the blankFor the expressionf(t)=tε(t)+2ε(t−2)−tε(t−2),f(3)=______ .
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周期T与频率f的关系为() A: T=f B: T=1/f C: T=2πf D: T=2π/f