POP广告是（ ）。
A: point of product
B: point of promotion
C: point of purchasing
D: point of point
A: point of product
B: point of promotion
C: point of purchasing
D: point of point
C
举一反三
- 【单选题】若有语句 int *point,a=4; 和 point=&a; 下面均代表地址的一组选项是 A. a,point,*&a B. &*a,&a,*point C. *&point,*point,&a D. &a,&*point ,point
- 【单选题】设Point为已定义的类,下面声明Point对象a语句正确的是() A. Point a=Point(); B. public Point a; C. Point a=new Point(); D. public Point a=new Point();
- 盘点: break point|game point|match point|set point
- 题 (1.0分) 题号:705 难度:中 第1章[br][/br]若有语句int *point,a=4;和 point=&a;下面均代表地址的一组选项是()。 A: a,point,*&a B: &*a,&a,*point C: *&point,*point,&a D: &a,&*point,point
- As we were ( ) giving up hope, a letter arrived. A: in the point of B: to the point of C: on the point of D: for the point of
内容
- 0
语句inta=10，*point=&a；（）其值不为地址。 A: point B: &a C: &point D: *point
- 1
Your question is ____________. A: beside the point B: point of view C: to point
- 2
Please _____ the mistakes in this sentence. A: Point to B: point for C: point out
- 3
下列代码中: class Point{ int x,y; public: Point(int a, int b=0); //① Point(Point &aPoint); //②Point(Point *p); //③ 默认的构造函数是 A: ① B: ② C: ③ D: 没有
- 4
Confidence is good ________, but you cannot be proud. A: up in a point B: up to a point C: up on a point D: up of a point