把下面代码补全:计算10的阶乘并输出。[br][/br] int result = 1; for(int i = 2; i <= 10; i++){ } System.out.println(“result=”+ result);
举一反三
- 下面程序段的输出结果是( )。 public class Test public static void main ( String[] args) int result=0; for ( int i=1;i<=5;i++) if ( i%2==0 ) continue; result + =i; System. out. println ("result is " + result ); A: result is 7 B: result is 8 C: result is 9 D: result is 10
- 以下代码执行的结果是:( )int i=2;int result = 0;switch (i) {case 1:result = result + i;case 2:result = result + i * 2;case 3:result = result + i * 3;}System.out.println(result); A: 0 B: 2 C: 4 D: 10
- 以下代码运行后,result的值为( )var result = 0; for (var i = 1; i <;= 10;i++) { result = result * i } A: 0 B: 1 C: 9的阶乘 D: 10的阶乘
- 下面程序段的输出结果是( )。 public class Test public static void main (String[] args) int n=10,result=0; for (int i=1;i<=n;i++) result+=i; System.out.println("result is"+result); A: A) result is 55 B: B) result is 45 C: C) result is 56 D: D) result is 54
- 下面是一个计算1至m的阶乘并依次输出的程序。请将程序补充完整。 #include double result=1; void fun( int j) { result=result*j; } void main() { int m,i; printf("Please enter an integer:"); scanf("%d", (1) ); for(i=1;i<=m;i++) { fun(i); printf("%d!=%.0f ", (2) ); } }