举一反三
- 以下程序运行后的输出结果是________。 #include "stdio.h" int f(int x); void main() { int n=1,m; m=f(f(f(n))); printf("%d",m); } int f(int x) {return x*2;}: 1/#/2/#/4/#/8
- 下面程序的运行结果是a=____,b=____。#include<;stdio.h>;int main( ){void f( int x , int y ) ;int a = 1 , b = 2 ;f( a , b ) ;printf( "a=%d,b=%d\n" , a , b ) ;return 0 ;}void f( int x , int y ){x = 100 ;y = 200 ;}
- 下列程序的运行结果是______ 。#include void main() { int n=0,m=1,x=2; if(!n) x-=1; if(m) x-=2; if(x) x-=3; printf("%d\n",x); }
- 下列程序的运行结果是 [12] 。 include <iostream. h> class Sample int x,y; public: Sample() x=y=0; Sample(int a, int b) x=a;y=b; void disp() cout<<" x=" <<x<<" , y="<<y<<end1; ; void main() Sample s1, s2(1, 2); s1. disp0; s2. disp ();
- 有以下程序: #include<iostream> using namespace std; int f(int,int); int main() { int i:1,x; x=f(i,i+1); cout<<x<<end1; return 0; } int f(int a,int b) { int c; c = a; if(a>b) c = 1; else if(a==b) c = 0; else c = -2; return c; } 运行后的输出结果是 。 A: 1 B: 0 C: -1 D: -2
内容
- 0
写出下列程序的输出结果( )。#include <stdio.h>void fun1( ){ int x=5; printf("x=%d\n",x);}void fun2(int x){ printf("x=%d\n", ++x);}void main( ){ int x=2; fun1( ); fun2(x); printf("x=%d\n", x);}
- 1
下列程序段的输出结果是 include void fun(int * X,int * y) {cout < < * X < < 下列程序段的输出结果是 #include<iostream.h> void fun(int * X,int * y) { cout < < * X < < * y; * X=3; * y=4; } void main( ) { int x=1,y=2; fun(&y,&x); cout < < X < < y < < end1; } A.2143 B.1212 C.1234 D.2112
- 2
以下程序的输出结果是_______________ int func(int x,int y) { return x+y; } void main( ) { int n,an,a0=1,a1=1; for(n=2;n<10;n++) { an=func(a0,a1); a0=a1; a1=an; } printf(“an=%d”,an); }
- 3
如下程序的输出是什么? #include [stdio.h] void Swap (int x, int y); int main() { int x = 1; int y = 2; printf ("x=%d,y=%d\n", x, y); Swap (x, y); printf ("x=%d,y=%d", x, y); } void Swap (int x, int y) { int temp; temp = x; x = y; y = temp; printf ("x=%d,y=%d\n", x, y); } A: x=1,y=2x=2,y=1x=2,y=1 B: x=1,y=2x=1,y=2x=2,y=1 C: x=1,y=2x=2,y=1x=1,y=2 D: x=1,y=2x=1,y=2x=1,y=2
- 4
请说出E类中[代码1]和[代码2]的输出结果。 class A{ double f(int x, double y){ return x+y; } int f(int x,int y) { return x*y; } } public class E{ public static void main(String args[ ] ){ A a=new A(); System.out.println(a.f(10,10)) ; // [代码1] System.out.println(a.f (10,10.0)) ; // [代码2] } }