举一反三
- 中国大学MOOC: 以下程序的输出结果是？number = 30if number % 2 == 0: print(number, is even)elif number % 3 == 0: print(number, is multiple of 3)
- 如果输入4,6.8,1,9.7，-2，则下列程序的输出结果是（） number=eval(input()) max=number whilenumber>0: number=eval(input()) ifnumber>max: max=number print(max)
- 下列程序段执行后,输出结果是: number = 20 try: if number < 0: number = -number print(number,end=) except: print("有异常发生",end=) else: print("平安无事",end=) finally: print("我很好我可以的",end=)
- 对一个列表里的数据进行奇偶数分离 numbers = [12, 37, 5, 42, 8, 3] even = [] odd = [] while len(numbers) > 0 : number = （ ） if(number % 2 == 0): even.append(number) else: odd.append(number) print even print odd
- 下列语句的执行结果是： number = 10 def myPrint(): global number number = 1 myPrint() print(number) A: 10 B: 1 C: 0 D: 报错
内容
- 0
下列语句的执行结果是： number = 10 def myPrint(): global number number = 1 print(number) myPrint() A: 10 B: 1 C: 0 D: 报错
- 1
下列语句的输出结果是： number = 4 while number >; 0: for i in range(number): print(i, end='') number -= 1 A: 0123012010 B: 012301201 C: 01230120 D: 0123012
- 2
假设 number 的输入是9。以下程序将显示什么？number = eval(input("Enter an integer: ")) isPrime = True for i in range(2, number): if number % i == 0: isPrime = False print("i is", i) if isPrime: print(number, "is prime") break else: print(number, "is not prime") A: i is 3 9 is prime B: i is 3 9 is not prime C: i is 2 9 is prime D: i is 2 9 is not prime
- 3
以下代码的输出结果是_________? int number = 6; while (number >; 0) { number -= 3; System.out.print(number + " "); } A: 60 B: 63 C: 30 D: 3 0 -3
- 4
int number_range=20;int number=2;boolean isprime=true;while(number<;number_range){isprime=true;for(int divlsor=2;divlsor<;=number/2;divlsor++){if(______){isprime=false;break;}}if(isprime){out.println(number+"<;br>;");}number++;}%>; A: divlsor%number==0 B: number%divlsor==0 C: divlsor/number==0 D: number/divlsor==0