• 2022-05-29
    Student类中存在String类型name属性,下列Student类的构造方法中,哪个是正确的?
    A: Student(String name){}
    B: Student(String name)
    C: Student(name)()
    D: NewStudent (String name){}
  • A

    举一反三

    内容

    • 0

      以下代码中,实例方法定义正确的是() A: class Student: def setName(self,name): self.name=name B: class Student: def setName(name): self.name=name C: class Student: def setName(self): self.name=name D: class Student: def setName(name,self): self.name=name

    • 1

      在C#中,下列代码的运行结果是( )(选一项)[br][/br] struct Student { public int age; public string name; public Student(int age,string name) { this.sge = sge; this.name = name; } } public class Test { static void Main() { Student stu1 = new Student(18,"小芳"); Student stu2 = new Student(24,"小刚"); stu2 = stu1; stu1.age = 30; stu1.name = "小燕"; Console.WriteLine(stu2.age); Console.WriteLine(stu2.name); } } A: 18 小芳 B: 18 小燕 C: 30 小燕 D: 30 小芳

    • 2

      表student中的包含两个字段,整型的id,字符串型的name。只显示表student中name列记录的SQL语句正确的是() A: select name from student B: select * from student C: select from name in student D: select name

    • 3

      已知函数getStudent()定义为public Student getStudent(int ID),下列四个选项中可以与getStudent构成重载的方法是 A: private Student getStudent(int ID) B: public String getStudent(int ID) C: Student getStudent(String name) D: public Student get(int ID)

    • 4

      若想查询student表中name为空值的记录,则正确的SQL语句是( )。 A: SELECT * FROM student WHERE name = NULL; B: SELECT * FROM student WHERE name like NULL; C: SELECT * FROM student WHERE name = 'NULL'; D: SELECT * FROM student WHERE name is NULL;