t=(1,2,3,4,5)，下列方法会导致异常的是（）。 A: t.index(1) B: t.count(3) C: len(t) D: t.sort()

现在有以下代码:t = (1,2.3,True,'westos')print(t.count('westos')) ##统计出现次数它的结果为1

I don't want them depending on someone they can't count on. 句中depend on 和count on 都是“依赖、依靠”的意思。（  ）

Don’t count on Mr. Wilson. He isn’t ________ to agree to take the position.

John was late for class again, but he couldn’t ______ his lateness. A: count for B: account for C: count on D: account in

以下程序段采用先根遍历方法求二叉树的叶子数,请在横线处填充适当的语句(注意:字符之间不要留空白)。 void countleaf (bitree ptr t,int &count) { /*根指针为t,假定叶子数 count 的初值 = 0 */ if (t!=NULL) { if ( (t->lchild==NULL) && (t->rchild==NULL)) (1)________; countleaf (t->lchild,count); countleaf(l->rchild,count); } }

count = 0while count < 5： print（ count） count = count + 2print( “Over!")

阅读以下程序public class Count{static int count;int number;public Count(){count = count + 1;number = count;}}class Test{public static void Main(){Count a = new Count();Count b = new Count();Count c = new Count();}}程序运行后，对象a的count值是（） A: 0 B: 1 C: 2 D: 3

count = 0 while count < 5: print (count, " 小于 5") count = count + 1 else: print (count, " 大于或等于 5")

下列if语句中，程序风格最规范的是（）。 A: if (count >;= 100) count = 0; B: if (count >;= 100) {count = 0;} C: if (count >;= 100)count = 0; D: if (count >;= 100){count = 0;}