求下列定解问题的解：[tex=27.143x5.214]fnpmC2J6JmQBLyo5NmGAz+76T2I8QMVR78YL0c5HwWMwa+PHGsEVCOgoI/sqK1gxptSPkHLx/FAesvrVw8SUmkKSE1BVGLIqTpfE8NLRGL3ldsoWxBhw+a4WkFJzZlPL+xX3RFW777xSNOBIzHgNdclEwBhd1eTiToTs5Nt+mGia+x0UvB9fjBmsw0GhBC01h7cGyqE9bscbSXaHOiGPnlBeF2qlxIbIsYEUjMe7LJ8BRIDU9esox5On9J4AIRDH7E80i9Li2qe7O1w3tCjva16ir7TRBqNp3NwiwtL8dPYAR6GCzoMkqWZRaEpMwP9IO2BgoxFvk8cC/Qx977jsKQ==[/tex]

求下列定解问题的解：[tex=27.143x5.214]fnpmC2J6JmQBLyo5NmGAz+76T2I8QMVR78YL0c5HwWMwa+PHGsEVCOgoI/sqK1gxptSPkHLx/FAesvrVw8SUmkKSE1BVGLIqTpfE8NLRGL3ldsoWxBhw+a4WkFJzZlPL+xX3RFW777xSNOBIzHgNdclEwBhd1eTiToTs5Nt+mGia+x0UvB9fjBmsw0GhBC01h7cGyqE9bscbSXaHOiGPnlBeF2qlxIbIsYEUjMe7LJ8BRIDU9esox5On9J4AIRDH7E80i9Li2qe7O1w3tCjva16ir7TRBqNp3NwiwtL8dPYAR6GCzoMkqWZRaEpMwP9IO2BgoxFvk8cC/Qx977jsKQ==[/tex]

求下列定解问题的解：[tex=27.143x5.214]fnpmC2J6JmQBLyo5NmGAz+76T2I8QMVR78YL0c5HwWMwa+PHGsEVCOgoI/sqK1gxptSPkHLx/FAesvrVw8SUmkKSE1BVGLIqTpfE8NLRGL3ldsoWxBhw+a4WkFJzZlPL+xX3RFW777xSNOBIzHgNdclEwBhd1eTiToTs5Nt+mGia+x0UvB9fjBmsw0GhBC01h7cGyqE9bscbSXaHOiGPnlBeF2qlxIbIsYEUjMe7LJ8BRIDU9esox5On9J4AIRDH7E80i9Li2qe7O1w3tCjva16ir7TRBqNp3NwiwtL8dPYAR6GCzoMkqWZRaEpMwP9IO2BgoxFvk8cC/Qx977jsKQ==[/tex]

‎荷载效应的基本组合中， SQk表示：‎‎注：QK为下角标‎ A: 永久作用的标准值效应 B: 可变作用的标准值效应 C: 预应力代表值效应 D: 荷载组合值效应

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4

共有4个站进行码分多址通信。4个站的码片序列为：a：（-1 -1 -1 +1 +1 -1 +1 +1） b：（-1 -1 +1 -1 +1 +1 +1 -1） c：（-1 +1 -1 +1 +1 +1 -1 -1） d：（-1 +1 -1 -1 -1 -1 +1 -1） 现收到这样的码片序列：（-1 +1 -3 +1 -1 -3 +1 +1），则（ ）发送1。