下列哪个信号不是周期信号（） A: Sin(0.5*pi*n) B: ACos(3*pi*n/7-pi/8） C: e(j*1.6*pi*n) D: e(j*n/8-pi)

下列程序段不能正确显示1！、2！、3！、4！的结果的是 。 A: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox( n)Next i B: Dim i%, j%, n%For i = 1 To 4 n = 1 For j = 1 To i n = n * j Next j MsgBox( n)Next i C: Dim j%, n%n = 1For j = 1 To 4 n = n * j MsgBox( n)Next j D: Dim j%, n%n = 1j = 1Do While j<=4 n=n*j MsgBox(n) j=j+1Loop E: Dim j%, n%n = 1j = 1Do n=n*j MsgBox(n) j=j+1Loop While j<=4

下面____程序段不能正确显示1!、2!、3!、4!的值。 A: For I=1 To 4 n=1 For j=1 to I n=n*j Next j Print n Next I B: For I=1 To 4 For j=1 to I n=1 n=n*j Next j Print n Next I C: n=1 For j=1 to 4 n=n*j Print n Next j D: n=1:j=1 Do While j<=4 n=n*j Print n j=j+1Loop

以下程序的运行结果是____ int<br/>main ( ) { int<br/>i, j, m, n;<br/>char<br/>a&#91; &#93;={ 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', '\0' }; char b&#91;10 &#93;={ 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', '\0'<br/>}; i= sizeof( a ); j=strlen( a ); m= sizeof( b ); n=strlen ( b ); printf ( "%d, %d, %d, %d\n", i, j, m, n ); return 0; } A: 9, 9, 10, 10 B: 8, 9. 8, 10 C: 9, 8, 10, 8 D: 9, 8, 9, 8

下列程序段能且只能显示1！、2！、3！、4！的值的是（ ）。 A: For i = 1 To 4 n = 1 For j = 1 To i n = n * j Next j MsgBox(n)Next i B: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox(n)Next i C: n = 1For i = 1 To 4 For j = 1 To 4 n = n * j MsgBox(n) Next jNext i D: n = 1j = 1Do While j <= 4 n = n * j j = j + 1LoopMsgBox(n)

以下程序的运行结果是( )。 void fun(int a&#91;&#93;&#91;3&#93;, int n) { int j; for(j=0;j A: 1 2 3 B: 2 5 8 C: 3 6 9 D: 7 8 9

下列程序段能分别正确显示1!、2!、3!、4!的值的是______。 A: For i = 1 To 4 n = 1 For j = 1 To i n = n * j MsgBox(n) Next jNext i B: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox(n)Next i C: n = 1For i = 1 To 4 For j = 1 To 4 n = n * j MsgBox(n) Next jNext i D: n = 1j = 1Do While j &lt;= 4 n = n * j MsgBox(n) j = j + 1Loop

若排列1294i56k7是偶排列，则i=,j= A: i=3 ,j= 8 B: i= 8,j= 3 C: i= 8 ,j=8 D: i= 3,j= 3

我（Wǒ）八点半（bādiǎnbàn）起床（qǐchuáng）。我（Wǒ）几点（jǐdiǎn）起床（qǐchuáng）？ A: 7:30 B: 8:15 C: 8:30 D: 8:08

中国大学MOOC: nums = [2, 7, 11, 15, 1, 8]l1 = []l = len(nums)for i in range(0, l-1): for j in range(i+1,l): if nums[i] + nums[j] == 9: n = (nums[i], nums[j]) l1.append(n)print(l1)