下面程序的功能是输出以下9阶方阵。请填空。 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 1 1 2 3 3 3 3 3 2 1 1 2 3 4 4 4 3 2 1 1 2 3 4 5 4 3 2 1 1 2 3 4 4 4 3 2 1 1 2 3 3 3 3 3 2 1 1 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 # include int main( ) { int a[10][10]，n，i，j，m； scanf("%d"，&n)； if(n%2= =0) m=n/2； else( )； for(i=0；i m=n/2+1
n–i–1
n–i–1

下列程序段能分别正确显示1!、2!、3!、4!的值的是______。 A: For i = 1 To 4 n = 1 For j = 1 To i n = n * j MsgBox(n) Next jNext i B: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox(n)Next i C: n = 1For i = 1 To 4 For j = 1 To 4 n = n * j MsgBox(n) Next jNext i D: n = 1j = 1Do While j <= 4 n = n * j MsgBox(n) j = j + 1Loop

下列程序段能且只能显示1！、2！、3！、4！的值的是（ ）。 A: For i = 1 To 4 n = 1 For j = 1 To i n = n * j Next j MsgBox(n)Next i B: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox(n)Next i C: n = 1For i = 1 To 4 For j = 1 To 4 n = n * j MsgBox(n) Next jNext i D: n = 1j = 1Do While j <= 4 n = n * j j = j + 1LoopMsgBox(n)

给出下面程序的运行结果。int i=0;main(){ int i=5;reset(i/2); printf("i=%d\n", i);reset(i=i/2); printf("i=%d\n", i);reset(i/2); printf("i=%d\n", i);workover(i); printf("i=%d\n", i);}workover(int i){ i=(i%i)*((i*i)/(2*i)+4);printf("i=%d\n", i);return(i);}reset(int i){ i=i<=2?5:0;return(i);}

下面____程序段不能正确显示1!、2!、3!、4!的值。 A: For I=1 To 4 n=1 For j=1 to I n=n*j Next j Print n Next I B: For I=1 To 4 For j=1 to I n=1 n=n*j Next j Print n Next I C: n=1 For j=1 to 4 n=n*j Print n Next j D: n=1:j=1 Do While j<=4 n=n*j Print n j=j+1Loop

【单选题】以下程序的输出结果是: void main() { int i,j,n,a[5]={3,4,1,2,-6}; for(i=0;i<5;i++) for(j=i+1;j<5;j++) if(a[j]<a[i]) { n=a[j];a[j]=a[i];a[i]=n; } for(i=0;i<5;i++) printf("%3d",a[i]); printf(" "); } A. 3 4 1 2 -6 B. 4 3 2 1 -6 C. -6 1 2 3 4 D. 4321-6

下列程序段不能正确显示1！、2！、3！、4！的结果的是 。 A: For i = 1 To 4 For j = 1 To i n = 1 n = n * j Next j MsgBox( n)Next i B: Dim i%, j%, n%For i = 1 To 4 n = 1 For j = 1 To i n = n * j Next j MsgBox( n)Next i C: Dim j%, n%n = 1For j = 1 To 4 n = n * j MsgBox( n)Next j D: Dim j%, n%n = 1j = 1Do While j<=4 n=n*j MsgBox(n) j=j+1Loop E: Dim j%, n%n = 1j = 1Do n=n*j MsgBox(n) j=j+1Loop While j<=4

下列程序输出结果是：（） int i,j,m,n; m=n=0; for(i=0;i&#91;2;i++) for(j=0;j<2;j++) if(j&#93;=i)m=1;n++; printf("n=%d\n",n); A: 4 B: 3 C: 2 D: 1

以下程序的输出结果是n=4 #include void main() { int i,n=0; for(i=2;i<5;i++) { do { if(i%3) continue; n++; } while(!i); n++; } printf("n=%d",n); }

正态分布<i>N</i>（10，2²）的中位数是（）。 A: 2 B: 4 C: 5 D: 10