证明恒等式:[tex=17.429x2.143]fsChRn1VBD/MIueIFkb3kDwRtbON9w3mMX6w1ZJ6Lt9nt3bU2L+BsYqlheCAFtVdQAtEZ9F3azud9kadu+qu9cUc1SqWin2rajDz70zxfx8=[/tex].

证明恒等式：[tex=16.286x2.143]fsChRn1VBD/MIueIFkb3kDwRtbON9w3mMX6w1ZJ6Lt9nt3bU2L+BsYqlheCAFtVdOVNMUEwSiFY8Raa91HexbMm+i1i11MyvBGfQtVnhTxo=[/tex]

证明下列恒等式[tex=17.286x2.143]fsChRn1VBD/MIueIFkb3kDwRtbON9w3mMX6w1ZJ6Lt9nt3bU2L+BsYqlheCAFtVdDcEckCud/2B2g4YFwfDMo6VoS2iiRjBxqWZBHrb5ekk=[/tex].

证明：[tex=9.643x2.143]fsChRn1VBD/MIueIFkb3kDwRtbON9w3mMX6w1ZJ6Lt9nt3bU2L+BsYqlheCAFtVdm/ji22ssiET1V6ZiwKhnhg==[/tex]，[tex=6.071x1.357]loZt+2XmEF86RZWPe6Zh3k7z88jfAcD5soICw/6rsEQ=[/tex].

试用戴维宁定理或者诺顿定理求图[tex=3.071x1.286]VBD/I1jJFzHHdBXCSQdnCA==[/tex]所示电路中通过电压源[tex=0.786x1.286]sgM90Q/VISKeSqiI8AMXRw==[/tex]的电流[tex=0.714x1.286]D09erOjBTmovPyUuLXjPSw==[/tex]。[img=462x226]17a8696a0295633.png[/img]

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4