• 2022-06-12 问题

    设随机变量X 和Y 相互独立,X ∼ N(0, 9), Y ∼ N(1, 4), 则 Z = X − Y 服从 ( ) 分布。 A: N(−1, 5); B: N(1, 13); C: N(−1, 13); D: N(1, 5).

    设随机变量X 和Y 相互独立,X ∼ N(0, 9), Y ∼ N(1, 4), 则 Z = X − Y 服从 ( ) 分布。 A: N(−1, 5); B: N(1, 13); C: N(−1, 13); D: N(1, 5).

  • 2022-06-12 问题

    以下代码中,最后x的值不是5的是哪一项?( ) A: x=1; while(x<5) { printf("%d\n",x); x++; } B: x=1; while(x<=5) { printf("%d\n",x); x++; } C: x=1; do { printf("%d\n",x); x++; }while(x<5); D: x=10; for( ;x>=6; x--) printf("%d\n",x);

    以下代码中,最后x的值不是5的是哪一项?( ) A: x=1; while(x<5) { printf("%d\n",x); x++; } B: x=1; while(x<=5) { printf("%d\n",x); x++; } C: x=1; do { printf("%d\n",x); x++; }while(x<5); D: x=10; for( ;x>=6; x--) printf("%d\n",x);

  • 2022-06-19 问题

    下列程序段的执行结果为______。 x = 0: y = 1 z = 1: n = 0 Do x = x + y + z n = n + 1 Loop While x < 10 Print x; n A: 10 5 B: x n C: 9 5 D: 10 6

    下列程序段的执行结果为______。 x = 0: y = 1 z = 1: n = 0 Do x = x + y + z n = n + 1 Loop While x < 10 Print x; n A: 10 5 B: x n C: 9 5 D: 10 6

  • 2022-05-29 问题

    声明一个变量为局部变量应该用( )。 A: Private Sub Command1 Click() n=5:x=1 Do X=X * I I=I + 1 Loop While I < n Print x End Sub B: Private Sub Command1_Click() n=5:X=1:I=1 Do X=X*I I=I + 1 Loop While I <n Print x End Sub C: Private Sub Command1_Click() n=5:X=1:I=1 Do X=X * I I=I + 1 Loop While I<=n Print X End Sub D: Private Sub Command1_Click() n=5:X=1:I=1 Do X=X * I I=I + 1 Loop While I>n Print X End Sub

    声明一个变量为局部变量应该用( )。 A: Private Sub Command1 Click() n=5:x=1 Do X=X * I I=I + 1 Loop While I < n Print x End Sub B: Private Sub Command1_Click() n=5:X=1:I=1 Do X=X*I I=I + 1 Loop While I <n Print x End Sub C: Private Sub Command1_Click() n=5:X=1:I=1 Do X=X * I I=I + 1 Loop While I<=n Print X End Sub D: Private Sub Command1_Click() n=5:X=1:I=1 Do X=X * I I=I + 1 Loop While I>n Print X End Sub

  • 2021-04-14 问题

    已知()x()(()n())()的()z()变换是()X()(()z())(),()ROC()是()|()z()|()>()a(),则()x(()-()n()-()5())()的()z()变换和()ROC()是()()A.()()z()-()5()X()(1/()z()),z()>()1/()a()B.()()z()5()X()(1/()z()),z()>()1/()a()C.()()z()-()5()X()(1/()z()),z()<()1/()a()D.()()z()5()X()(1/()z()),z()<()1/()a

    已知()x()(()n())()的()z()变换是()X()(()z())(),()ROC()是()|()z()|()>()a(),则()x(()-()n()-()5())()的()z()变换和()ROC()是()()A.()()z()-()5()X()(1/()z()),z()>()1/()a()B.()()z()5()X()(1/()z()),z()>()1/()a()C.()()z()-()5()X()(1/()z()),z()<()1/()a()D.()()z()5()X()(1/()z()),z()<()1/()a

  • 2021-04-14 问题

    已知随机变量X~B(n,1/2),且P{X=5}=1/32,则n=___________

    已知随机变量X~B(n,1/2),且P{X=5}=1/32,则n=___________

  • 2022-06-30 问题

    若X~N(3,0.2),Y~N(2,0.3),且X与Y相互独立,则X+Y~( ) A: N(5, 0.1) B: N(5, 0.5) C: N(1, 0.1) D: N(1, 0.5)

    若X~N(3,0.2),Y~N(2,0.3),且X与Y相互独立,则X+Y~( ) A: N(5, 0.1) B: N(5, 0.5) C: N(1, 0.1) D: N(1, 0.5)

  • 2022-06-09 问题

    下边循环执行完后,n为( ). for ( x= 1; x< 5; x++ ) for ( y= n = 0; y< x; y++, n = n +x) ; A: 16 B: 10 C: 14 D: 5

    下边循环执行完后,n为( ). for ( x= 1; x< 5; x++ ) for ( y= n = 0; y< x; y++, n = n +x) ; A: 16 B: 10 C: 14 D: 5

  • 2022-06-19 问题

    已知随机变量X~B(n,1/2),且P{X=5}=1/32,则n=___________ A: 5 B: 6 C: 7 D: 8

    已知随机变量X~B(n,1/2),且P{X=5}=1/32,则n=___________ A: 5 B: 6 C: 7 D: 8

  • 2021-04-14 问题

    已知()y()=()ln()x(),则()y()(()n())()=()。A.()(()−()1())()n()n()!()x()−()n()"()role="presentation">()(()−()1())()n()n()!()x()−()n();()B.()(()−()1())()n()(()n()−()1())()!()x()−()2()n()"()role="presentation">()(()−()1())()n()(()n()−()1())()!()x()−()2()n();()C.()(()−()1())()n()−()1()(()n()−()1())()!()x()n()"()role="presentation">()(()−()1())()n()−()1()(()n()−()1())()!()x()-n();()D.()(()−()1())()n()−()1()n()!()x()−()n()+()1()"()role="presentation">()(()−()1())()n()−()1()n()!()x()−()n()+()1().

    已知()y()=()ln()x(),则()y()(()n())()=()。A.()(()−()1())()n()n()!()x()−()n()"()role="presentation">()(()−()1())()n()n()!()x()−()n();()B.()(()−()1())()n()(()n()−()1())()!()x()−()2()n()"()role="presentation">()(()−()1())()n()(()n()−()1())()!()x()−()2()n();()C.()(()−()1())()n()−()1()(()n()−()1())()!()x()n()"()role="presentation">()(()−()1())()n()−()1()(()n()−()1())()!()x()-n();()D.()(()−()1())()n()−()1()n()!()x()−()n()+()1()"()role="presentation">()(()−()1())()n()−()1()n()!()x()−()n()+()1().

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