程序段如下: x=[1,2,3] y=["a","b","c"] print(list(zip(x,y)))print函数输出的结果是( )
A: [( 'a':1), ('b:2), ('c':3)]
B: [(1,2,3),("a","b","c")]
C: [(1, 'a'), (2, 'b'), (3, 'c')]
D: [{1:'a'}, {2:‘b'}, {3:'c'}]
A: [( 'a':1), ('b:2), ('c':3)]
B: [(1,2,3),("a","b","c")]
C: [(1, 'a'), (2, 'b'), (3, 'c')]
D: [{1:'a'}, {2:‘b'}, {3:'c'}]
举一反三
- 下面代码的输出结果是( )。 t=[1,2,3] s=tuple(t) print(t,s) A: [1, 2, 3] [1, 2, 3] B: (1, 2, 3) (1, 2, 4) C: [1, 2, 3] (1, 2, 3) D: (1, 2, 6)[1, 2, 3]
- 以下程序的输出结果是: L2 = [1,2,3,4] L3 = L2.reverse() print( L3) A: [1,2,3,] B: [3, 2, 1] C: None D: [4, 3, 2, 1]
- 已知函数定义:def demo(**p): print(p)调用该函数demo(x=1,y=2,z=3),下面输出正确的是: A: {'x': 1, 'y': 2, 'z': 3} B: 1,2,3 C: (1, 2, 3) D: [1, 2, 3]
- print(1,2,3,end="*")的输出结果是 。 A: 1,2,3,* B: 1 2 3* C: 1*2*3 D: 1,2,3*
- x = [ 1, 2 ] y = x x += y print(x) 上述代码输出结果为____。 A: [ 1, 2 ] B: [ 1, 2, 1 ] C: [ 2, 1, 2, 1 ] D: [ 1, 2, 1, 2]