以下程序运行结果是（）。#includeiostreamusing namespace std;void sub(int x, int *y,int *z){*y=*y-10;*y=*z+x;}int main(){int a=10,b=12,* pa,* pb;pa=a;pb=b;sub(b-a,pa pa);coutaendl;return 0;}
A: 9
B: 4
C: 7
D: 2
A: 9
B: 4
C: 7
D: 2
举一反三
- 下列程序运行后的输出结果是：_____#includestdio.hvoid fun( int *pa, int pb ) { int pt; pt = *pa, *pa = pb, pb = pt;}int main( ){ int x=1, y=2; fun(x, y); printf(%d, x==y); return 0;}
- 以下代码的输出是 ：void swap( int *pa, int *pb ) { int pt; pt = *pa, *pa = *pb, *pb = *pa; } int main(void) { int x=1, y=2; swap(&x, &y); printf("%d%d", x, y); }
- 以下代码的输出是 ：void f( int *pa, int *pb ) { int pt; pt = *pa, *pa = *pb, *pb = *pa; } int main(void) { int x=1, y=2; f(＆x, ＆y); printf("%d%d", x, y); }
- 中国大学MOOC: 以下程序段的输出是( )。void swap(int *pa, int *pb) { int pt; pt = *pa, *pa = *pb, *pb = *pa;}int main(void){ int x=1, y=2; swap(&x, &y); printf(%d %d, x, y);}
- 若有以下程序： #include＜stdio.h＞ void sub(double x, double*y, double*z) { *y=*y-1.0; *z=*z+x; } main() {double a=2.5, b=9.0, *pa, *pb; pa=&a; pb=&b; sub(b-a, pa, pa); printf("%f\n", a); } 程序的输出结果是 A: 9.000000 B: 1.500000 C: 8.000000 D: 10.500000