以下有关取模运算的代码,其运算结果正确的是。$num1 = -10; $num2 = -3; $num3 = 10; $num4 = -3; echo $num3%$num4-$num1%$num2; ?>;
A: -2
B: 2
C: 0
D: 1
A: -2
B: 2
C: 0
D: 1
举一反三
- 编写一个函数判断客户输入一个数字为1位、2位还是更多为，代码如下：请补全空下的代码num=int(input("输入一位或两位的数字:"))n='0'(1)n='1'(2)n='2'(3)d='>;2'print(n+"位数。”) A: 1: if num>;-10 and num<;10:2: eilf num >;-100 and num<;100:3: else: B: 1: if num>;10 and num<;-10:2: eilf num >;-100 and num<;100:3: else: C: 1: if num>;-10 and num<;10:2: eilf num <;-100 and num>;100:3: elif: D: 1: if num>;-100 and num<;100:2: eilf num >;-10 and num<;10:3: else:
- 下列程序的输出结果是（） num = 27 count = 0 while num > 0: if num % 2 == 0: num /=2 elif num % 3 ==0: num /= 3 else: num -=1 count += 1 print (count)
- 哪行代码会导致错误？（）num=[5,4,3,[2],1]print(num[0])print(num[3][0])print(num[5])
- 【单选题】在Java语言中,经过如下运算后,num的值为()int num = 0;num = 2>;3?0:1; A: 0 B: 1 C: 2 D: 3
- 执行如下代码片段后，num的值为：int num = 5;num = (num % 2) == 0 ? num – 1 : num + 1; A: 1 B: 4 C: 5 D: 6