写出下列配合物的化学式。[tex=14.143x1.286]+y3cryqS4R6t0RQsJqR73SJOMYQ26LynWE22rIy+po0PyLr8LNV8lasC0jzeauxq8Bq8WImKaKSahzoBWY7L/A==[/tex]
举一反三
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- 【单选题】rev(c(1,3,2,6,7,8,8,1,1,0))的运行结果 ? A. [1] 0 1 1 1 2 3 6 7 8 8 B. [1] 1 3 2 6 7 8 8 1 1 0 C. [1] 0 1 1 8 8 7 6 2 3 1 D. [1] 8 8 7 6 3 2 1 1 1 0
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 已知x(n)={1, 2, 3}，y(n)={1, 2, 1}，则x(n)*y(n)=________。（下划线表示n=0） A: {1, 4, 8, 8, 3} B: {1, 4, 8, 8, 3} C: {1, 4, 8, 8, 3} D: {1, 4, 8, 8, 3}