求图[tex=1.786x1.286]ZhVlcXq80nIHBcECJWLKkQ==[/tex]所示各系统的阶跃响应。[img=261x146]17aec839a617c6a.png[/img]

2022-07-28

求图[tex=1.786x1.286]ZhVlcXq80nIHBcECJWLKkQ==[/tex]所示各系统的阶跃响应。[img=261x146]17aec839a617c6a.png[/img]

答案：

[tex=15.0x2.357]KuqUiJ/3TOa3n7K9OoW0k2ozk0jrJPdgO+O8MhpzWsxCoixgBGHu9YrePwjZWcwZoUfuQ6nKkqweO9n83LS94Q==[/tex]对于单位阶跃响应[tex=14.143x6.643]UD5Uh4Sf0JOreHxD3gt15nRDamnIXClPAuW9j3VFISMw00ve9m4UVhjBciCrapYGru/TqxHILEjF37VONrfaiv15MVh0N+U73qB2jYhB2w3wb163Cp8/N9hAz31acNlP0ZyY1wlx731qBMhHrvpXM/eyk60qemd8K7oCQVOC9kVdx+5MY/X+2f1KdmTdfZO2eO50TouMHWXZ9YAvbaQTuQ==[/tex]特解为[tex=3.429x1.357]AexX6nMOgeiByf0z44GdnQ==[/tex] 特征方程 [tex=6.857x2.357]BlyU32YV/JdJXyXBMovey7W8u7IrVhGSHt+wfLaxddjgbFc+kg5YGInw35jWWtH58WfSo9jxyuCQ5caPTjb11Q==[/tex]特征根为 [tex=7.643x2.357]ujxl/8R5Q+XaK3WBnrRJm7I6CBZsdcAiEzEEgu1TLHtK/GjfKkP1N5p3OPs8q+YGa7FQq+x4M2apc/nL9V5BLg==[/tex]令 [tex=13.857x3.0]fXc0a4Q/ktsOvVSpITyypCKjput5LORD24aqAV/TkX6FfO4nxgvVH7vV2/S47bPsN+ALDHL52XlkNFGHCJvQ5+qIIP4PYTlpZKF4uE7bIPc=[/tex]代入[tex=4.0x1.357]lUSCCVzDLvbJ2YSCXkEblw==[/tex]得[tex=17.714x8.929]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[/tex]

举一反三

内容

0
电路如图 5-7 所示，激励为[tex=1.643x1.357]j6KcqgyprXeRIkkNI3dxdw==[/tex]，响应为[tex=1.5x1.357]4oplQ+uBNX3MZ46HijPjsQ==[/tex]，求冲激响应与阶跃响应。[img=368x177]17d5c1ec340ea5b.png[/img]
1
试用网孔电流法求解图题[tex=2.714x1.286]dzci7D6lc2IKY55QLBUaDQ==[/tex]所示电路中的电流[tex=1.857x1.286]05K5qYL8eTE8Exk30ObFXQ==[/tex]。[img=261x146]17cffde3293b13e.png[/img]
2
图[tex=1.786x1.286]caQXs1xVuE9w+2rlI+Vt2Q==[/tex]所示为两级比例运算放大电路，求[tex=1.0x1.286]KhtItbtCeW15Kau+r6exDQ==[/tex]与[tex=1.0x1.286]yHkZY53YG71ZQn50EFjMdQ==[/tex]的关系式。[img=456x245]17a9400f2a32cbe.png[/img]
3
用诺顿定理求图[tex=1.786x1.286]dFmZMG0GiL/une2H3l3sqg==[/tex]（练习题[tex=2.0x1.286]SKoPBLBi1gHFFA4FTANSAw==[/tex]）所示电路中的电流[tex=0.714x1.214]0ORdTuKUFMjJNSVTzCwMAw==[/tex]。[img=389x196]17a86925f09062f.png[/img]
4
试求图[tex=1.786x1.286]NYRfonho/J+q0OIlLt9MAg==[/tex]所示图形对形心轴[tex=0.5x1.286]asctJDWpGaq/ETe64ANZ1Q==[/tex]的惯性矩[tex=1.071x1.286]hv4j+Jak6wLMjki9kEBA+Q==[/tex]。[img=252x229]17d12df04d35d77.png[/img]