• 2022-06-28
    已知熵的一般关系式为[tex=9.571x2.929]20PGHDC9pZuSWWXmmUzdcRlDGX5YIlS+Z4K3LRTHQYDXxMi6t9XoHmJZq9NMf0y3RQDUl9zO0/QIu+JAYNqZDJ96vw0LRxW2rTodtlt3EvMNqcECPeJXqPTItNXx90e4[/tex]试推导出焦耳-汤姆逊系数 (或称绝热节流系数)[tex=1.0x1.0]Y2oYuCj8qd+AHLI4MdV3nA==[/tex] 的一般关系式,并证明理想气体的 [tex=2.286x1.214]c4IhssYkj11b/YTq5HoziA==[/tex]。
  • [tex=5.786x1.214]XqAKRwJmdtjGU4fvH1FBlA==[/tex][tex=23.929x3.357]LhDoqhheGNGVWYLHUK3ld9ZI6/IOfSLR5i/lsjeQqkEGDGpVBeNrEtLSPGMRqzWiws1XpyLaeBkvADSuMxRda+lUZ8+7sdzvXXalf70HMSIFzclzElTjkI8Y2UXW5sA3Ogw6yMZtAQbapzev0xgYOyuGCHoTeN1vyf6ZObdN+1/cW2EpMsdKANBJkKl4Q++mwcHbFo2VxW9LZlrnmyLe9Fh+tZnwVbEHLzTwO87G3dE=[/tex]于是 [tex=14.214x3.357]WdS4GnDLcLYPj8ywtRnMkmNigbKp99swOwtyWjyCG13iULM+cU4hh+HyuN3VJV6Mw8toebC0rXNWybXRnIg9D6yVNyMqCXEWT4x41nORcK9KboJ8JJo6pzD5Qf8vrLkOHrXe5NKH/6u7bb2Tr5L1wA==[/tex] [tex=1.571x1.357]t4j8DiUnyf9QhxbEEfhEow==[/tex]状态参数 [tex=4.214x1.357]BYkgY2BSzwDLPiN6Dy2/Yg==[/tex] 又可以写成全微分形式,即[tex=11.929x2.929]WlPE90n6ZRrPmy+a3HANHL/aHSmTqsb1iP/rzGFyDtOUh1ecuef9901hfgPDLxjz4rnoQwaoq/DC1l3FmtyxQGCGj/E/R+w6cFxOlmWNuv+lAOxvSvjvn0AElhHcoS0PTtVI+9CG99s8HlGq6OLuqQ==[/tex]   [tex=1.571x1.357]6ZdvBUUXTfu1lpc1bzYo0Q==[/tex]对比式[tex=3.786x1.357]PdtINabUzg7KttXhGLXgjA==[/tex]得焦-汤系数的一般表达式[tex=11.929x4.357]b/DNuSL1OfQ/WSjXoAh/uXgv1GpVAVoAI+shjLMmLkAUjNmDrLd5ZBTO4GpbdrnWWPMMeQBQEFVEdCcrYsSmge4x2fRDrMbw1zjdrx6aiVcbd3QYCDMoAPZykWnt5zK1xSRSJeFXSOSnjuEBP4q86GRd8MNycKKj8hm20D8IcoEWCbEho7KIbZceoZ4RY4o4[/tex]对于理想气体, [tex=3.643x1.286]pSqXu9SRm6bxvQj6ySPNVmnn7dA/JyCEiSWjwQ0776k=[/tex], 于是把 [tex=5.643x2.929]Do4JlNuzOZNqOZfDB1mImjG5pgaL4XNqYTZozSpu7HpS6ZmE+Q8PTkiM1ukPVWdKXc5UYhFbGIi1t1FVwyUXxmw9kBlSqo+QLvVVvw17XA0=[/tex] 代入上式得[tex=10.714x2.714]/cIPNg0hc/sB3XEXHznW9pWlJvQ1WR6OC0jxI0nt8y+w4KZzH5PFCxH77VbbP1uj9yRyXQ+8Rgvikiqoh01MpAVOtTNwxtHzq6FEyh+HxV4=[/tex]

    内容

    • 0

      已知直线的一般方程\( \left\{ {\matrix{ {x - 2y - z + 4 = 0} \cr {5x + y - 2z + 8 = 0} \cr } } \right. \), 则其点向式方程为( ) A: \( { { x - 2} \over 2} = {y \over { - 3}} = { { z - 4} \over {11}} \) B: \( {x \over 5} = {y \over { - 3}} = { { z - 4} \over {11}} \) C: \( { { x - 2} \over 5} = { { y + 1} \over { - 3}} = { { z - 4} \over {11}} \) D: \( { { x - 2} \over 2} = { { y + 1} \over { - 3}} = { { z - 4} \over {11}} \)

    • 1

      set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}

    • 2

      ‌下面说法错误的是( )。‌‌知识点:列表推导式‌ A: dict([(x, x**2) for x in range(6)]) 创建的字典是{0: 0, 1: 1, 2: 4, 3: 9, 4: 16, 5: 25} B: [[x*3+y for y in range(1,4)] for x in range(3)] 创建的是二维列表 [[1, 2, 3], [4, 5, 6], [7, 8, 9]] C: number = [-2, 4, 6, -5]string = 'ab'z = [(i, j) if i>0 else (-i, j) for i in number for j in string]这段代码创建的列表为[(2, 'a'), (2, 'b'), (4, 'a'), (4, 'b'), (6, 'a'), (6, 'b'), (5, 'a'), (5, 'b')] D: ' '.join([i for i in range(1,11)])的运算结果为字符串'1 2 3 4 5 6 7 8 9 10'

    • 3

      设DES加密算法中的一个S盒为: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0 1 2 3 14 4 13 1 2 15 11 8 3 10 6 12 5 9 0 7 0 15 7 4 14 2 13 1 10 6 12 11 9 5 3 8 4 1 14 8 13 6 2 11 15 12 9 7 3 10 5 0 15 12 8 2 4 9 1 7 5 11 A: 1010 B: 0001 C: 1011 D: 0111

    • 4

      下面语句的输出结果是?range(len('HelloWorld')) A: [1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11] B: 11 C: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] D: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]