下列表达式可以作为判断一个整数number为奇数的是（）
A: number // 2 == 1
B: number // 2 == 0
C: number % 2 == 1
D: number / 2 == 1
A: number // 2 == 1
B: number // 2 == 0
C: number % 2 == 1
D: number / 2 == 1
C
举一反三
- Analyze the following code: Code 1: int number = 45; bool even; if (number % 2 == 0) even = true; else even = false; Code 2: int number = 45; bool even = (number % 2 == 0); A: Code 1 has compile errors. B: Code 2 has compile errors. C: Both Code 1 and Code 2 have compile errors. D: Both Code 1 and Code 2 are correct, but Code 2 is better.
- 以下程序的输出结果是___________。 number = 10 if number % 2 == 0: print(number, 'is even') elif number % 5 == 0: print(number, 'is multiple of 2')
- int number_range=20;int number=2;boolean isprime=true;while(number<;number_range){isprime=true;for(int divlsor=2;divlsor<;=number/2;divlsor++){if(______){isprime=false;break;}}if(isprime){out.println(number+"<;br>;");}number++;}%>; A: divlsor%number==0 B: number%divlsor==0 C: divlsor/number==0 D: number/divlsor==0
- Your______，Please.(请______您的号牌。)(1)number……亮出(2)number……举高(3)anumber……出示 A: (1) B: (2) C: (3)
- Your______，Please.(请______您的号牌。)(1)anumber……出示(2)number……亮出(3)number……举高 A: (1) B: (2) C: (3)
内容
- 0
The girl is working in the: (1) The room number the girl will rent: (2) The price to be paid is: (3) The girl’s phone number is: (4) 2（）
- 1
下列语句的执行结果是： number = 10 def myPrint(): global number number = 1 myPrint() print(number) A: 10 B: 1 C: 0 D: 报错
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下列语句的执行结果是： number = 10 def myPrint(): global number number = 1 print(number) myPrint() A: 10 B: 1 C: 0 D: 报错
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中国大学MOOC: 以下程序的输出结果是？number = 30if number % 2 == 0: print(number, is even)elif number % 3 == 0: print(number, is multiple of 3)
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int mystery ( int number ) { if ( number <= 1 ) return 1; else return number * mystery( number – 1 ); }