(x+x/1)的平方=9则(x-x/1)
举一反三
- 化简：x平方+x/x-1除以x平方-1/x平方-2x+1-（2x-1）
- 以4，9，1为为插值节点，求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)
- （X-1）（X+1）=X的平方-1（X-1）（X的平方+X+1）=X的立方-1（X-1）（X的立方+X的平方+X+1）=X的四次方-
- 已知f(x)=x^2—1,求f(x+x^2).
- (x+x/1)的平方=9则(x-x/1)