配制0.1mol/L的NaOH溶液1L,需加入的NaOH为 MNaOH=40g/mol

配制500毫升0.1mol/LNaOH溶液,需要称取固体NaOH（）克？（MNaOH＝40g/mol）（5.0分）

要配制0.5mol/LNaOH溶液500mL，需称取NaOH固体多少克？MNaOH＝40g/mol（5.0分）

配制浓度为0.1mol/L的NaOH溶液500ml,需称取固体NaOH约MNaOH=40g/mol:

室温下，用铂作两极，电解1MNaOH溶液，阴极上发生的电极反应为：（） A: Na++e─→Na B: HO+½O2+2e─→2OH C: 2H+2e─→H D: 2OH─→HO+½O+2e

室温下,用铂作两极,电解1MNaOH溶液,阴极上发生的电极反应为: A: Na++e─→Na; B: H2O+½O2+2e─→2OH-; C: 2H2O+2e─→H2+2OH-; D: 2OH-─→H2O+½O2+2e。

智慧职教: 称取NaOH样品0.5000g溶于锥形瓶中，用0.1000mol/L盐酸标准溶液滴定到甲基橙变橙为终点，消耗盐酸25.00ml，求NaOH的百分含量。(MNaOH=40g/mol)

将0.25molHCl气体溶于水形成500mL溶液，MHCl=36.5g/mol，MNaOH=40g/mol。(1)所得盐酸的物质的量浓度为 mol/L（保留两位有效数字）(2)向其中加入 g NaOH才能中和完全。（保留两位有效数字）(3)若不考虑加入NaOH对体积造成的影响，所得NaCl的物质的量浓度为 mol/L（保留两位有效数字）

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1