• 2022-06-05 问题

    函数$z=\arcsin\dfrac{1}{~\sqrt{x+y}~}$的定义域为( ) A: $\left\{(x,y)\left|~x+y\geq<br/>0\right.\right\}$; B: $\left\{(x,y)\left|~x+y\geq<br/>1~\text{或}~x+y\leq<br/>-1 \right.\right\}$; C: $\left\{(x,y)\left|~x+y\geq<br/>1\right.\right\}$; D: $\left\{(x,y)\left|~x+y\geq<br/>\dfrac{4}{~\pi^2~}\right.\right\}$.

    函数$z=\arcsin\dfrac{1}{~\sqrt{x+y}~}$的定义域为( ) A: $\left\{(x,y)\left|~x+y\geq<br/>0\right.\right\}$; B: $\left\{(x,y)\left|~x+y\geq<br/>1~\text{或}~x+y\leq<br/>-1 \right.\right\}$; C: $\left\{(x,y)\left|~x+y\geq<br/>1\right.\right\}$; D: $\left\{(x,y)\left|~x+y\geq<br/>\dfrac{4}{~\pi^2~}\right.\right\}$.

  • 2022-06-19 问题

    \(\left\{ {\left( {x,y} \right)\left| {2 \le {x^2} + {y^2} \le 4} \right.} \right\}\)是闭区域.

    \(\left\{ {\left( {x,y} \right)\left| {2 \le {x^2} + {y^2} \le 4} \right.} \right\}\)是闭区域.

  • 2022-05-31 问题

    研究生招考录取过程中,有5%的学生被保送录取,其余的有30%的学生参加研究生考试并初试合格进入复试;复试考生中80%被录取,剩余复试者可通过调剂,有0.5的机会被录取。求:1)一位考生被录取的概率;2)已知某考生已被录取,则他是通过调剂被录取的概率。(1). 设 \(A,B,C\) 为三个事件,且 \( P\left( \mbox{A} \right)&gt;0<br/>\),则有 \( P\left( {ABC} \right)= \)( )。 A: \( P\left( {ABC} \right)=P\left( A \right)P\left( {C\left| A<br/>\right.} \right). \) B: \( P\left( {ABC} \right)=P(A)P\left( {BC} \right)P\left(<br/>{A\left| {BC} \right.} \right). \) C: \( P\left( {ABC} \right)=P(A)P\left( B \right)P\left( {C\left|<br/>{AB} \right.} \right). \) D: \( P\left( {ABC} \right)=P\left( A \right)P\left( {B\left| A<br/>\right.} \right)P(C\vert AB) \)

    研究生招考录取过程中,有5%的学生被保送录取,其余的有30%的学生参加研究生考试并初试合格进入复试;复试考生中80%被录取,剩余复试者可通过调剂,有0.5的机会被录取。求:1)一位考生被录取的概率;2)已知某考生已被录取,则他是通过调剂被录取的概率。(1). 设 \(A,B,C\) 为三个事件,且 \( P\left( \mbox{A} \right)&gt;0<br/>\),则有 \( P\left( {ABC} \right)= \)( )。 A: \( P\left( {ABC} \right)=P\left( A \right)P\left( {C\left| A<br/>\right.} \right). \) B: \( P\left( {ABC} \right)=P(A)P\left( {BC} \right)P\left(<br/>{A\left| {BC} \right.} \right). \) C: \( P\left( {ABC} \right)=P(A)P\left( B \right)P\left( {C\left|<br/>{AB} \right.} \right). \) D: \( P\left( {ABC} \right)=P\left( A \right)P\left( {B\left| A<br/>\right.} \right)P(C\vert AB) \)

  • 2022-06-05 问题

    Copyright is an intellectual property right which relates to the expression of an idea, rather than to the idea itself. Copyright is an (1) … right and the owner does not need to apply to (2) … his or her right or to pay for that right. It protects (3) … types of work, (2)为

    Copyright is an intellectual property right which relates to the expression of an idea, rather than to the idea itself. Copyright is an (1) … right and the owner does not need to apply to (2) … his or her right or to pay for that right. It protects (3) … types of work, (2)为

  • 2022-06-14 问题

    A: This toothache is killing me.B: If I am right, this is the third time you’ve had it this month.A: You are right. (). A: It’s all right. B: It’ll be gone. C: I have no method. D: I’m fed up with it.

    A: This toothache is killing me.B: If I am right, this is the third time you’ve had it this month.A: You are right. (). A: It’s all right. B: It’ll be gone. C: I have no method. D: I’m fed up with it.

  • 2022-07-26 问题

    曲线\( \left\{ {\matrix{ { { x^2} + {y^2} = {z^2}} \cr { { z^2} = y} \cr } } \right. \)在坐标面\( yoz \) 上的投影曲线方程为( ) A: \( \left\{ {\matrix{ { { x^2} + { { \left( {y - {1 \over 2}} \right)}^2} = {1 \over 4}} \cr {z = 0} \cr } } \right. \) B: \( \left\{ {\matrix{ { { z^2} = y} \cr {x = 0} \cr } } \right. \) C: \( \left\{ {\matrix{ {z = {y^2}} \cr {x = 0} \cr } } \right. \) D: \( \left\{ {\matrix{ { { y^2} + { { \left( {x - {1 \over 2}} \right)}^2} = {1 \over 4}} \cr {z = 0} \cr } } \right. \)

    曲线\( \left\{ {\matrix{ { { x^2} + {y^2} = {z^2}} \cr { { z^2} = y} \cr } } \right. \)在坐标面\( yoz \) 上的投影曲线方程为( ) A: \( \left\{ {\matrix{ { { x^2} + { { \left( {y - {1 \over 2}} \right)}^2} = {1 \over 4}} \cr {z = 0} \cr } } \right. \) B: \( \left\{ {\matrix{ { { z^2} = y} \cr {x = 0} \cr } } \right. \) C: \( \left\{ {\matrix{ {z = {y^2}} \cr {x = 0} \cr } } \right. \) D: \( \left\{ {\matrix{ { { y^2} + { { \left( {x - {1 \over 2}} \right)}^2} = {1 \over 4}} \cr {z = 0} \cr } } \right. \)

  • 2022-07-27 问题

    5.下列函数中,在其定义域上有最大值和最小值的是()。 A: $f(x)=\left\{ \begin{array}{*{35}{l}} \ln \left| x \right|,\ \ \ x\ne 0 \\ 0,\ \ \ \ \ \ \ \ x=0 \\ \end{array} \right.$ B: $f(x)=\ln \left( \left| x \right|+1 \right)\ x\in [-1,1]$ C: $f(x)=\ln \left| x \right|,\ \ \ x\in [-1,1]\backslash \{0\}$ D: $f(x)=\left\{ \begin{array}{*{35}{l}} \ln \left| x \right|,\ \ \ 0\lt |x|\lt 1 \\ 0,\ \ \ \ \ \ \ \ x=0 \\ \end{array} \right.$

    5.下列函数中,在其定义域上有最大值和最小值的是()。 A: $f(x)=\left\{ \begin{array}{*{35}{l}} \ln \left| x \right|,\ \ \ x\ne 0 \\ 0,\ \ \ \ \ \ \ \ x=0 \\ \end{array} \right.$ B: $f(x)=\ln \left( \left| x \right|+1 \right)\ x\in [-1,1]$ C: $f(x)=\ln \left| x \right|,\ \ \ x\in [-1,1]\backslash \{0\}$ D: $f(x)=\left\{ \begin{array}{*{35}{l}} \ln \left| x \right|,\ \ \ 0\lt |x|\lt 1 \\ 0,\ \ \ \ \ \ \ \ x=0 \\ \end{array} \right.$

  • 2022-06-07 问题

    The meaning of “That is what going to war means; it means saying that might is right." (Last sentence of Paragraph 2) is that ________. A: those who fight believe that the winner is right and the loser wrong. B: only those who are powerful have the right to go to war. C: those who are right should fight against those who are wrong. D: in a war only those who are powerful will win.

    The meaning of “That is what going to war means; it means saying that might is right." (Last sentence of Paragraph 2) is that ________. A: those who fight believe that the winner is right and the loser wrong. B: only those who are powerful have the right to go to war. C: those who are right should fight against those who are wrong. D: in a war only those who are powerful will win.

  • 2022-10-26 问题

    设\(D = \left\{ {(x,y)\left| { { x^2} + {y^2} \le 9,x \ge 0,y \ge 0} \right.} \right\}\),则\(\int\!\!\!\int\limits_D {(x + 3y)} d\sigma = \)______

    设\(D = \left\{ {(x,y)\left| { { x^2} + {y^2} \le 9,x \ge 0,y \ge 0} \right.} \right\}\),则\(\int\!\!\!\int\limits_D {(x + 3y)} d\sigma = \)______

  • 2021-04-14 问题

    Not only he but also we _____ right. He as well as we _____ right.

    Not only he but also we _____ right. He as well as we _____ right.

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