• 2022-06-12
     求下列空间曲线的弧长 [tex=5.143x3.357]fnpmC2J6JmQBLyo5NmGAz4YMSUI/hZpVsWqUQC5mevKxK/kjVp4JIu9uG8p+q3X0Jxnp9snz+/kjrnPOeN7T4DTHse7fMsGotGth9+Z3mSs=[/tex] 介于点[tex=3.214x1.357]Ttim9kVbyq0HPRRwWDwHtA==[/tex]与点[tex=3.214x1.357]I0dqrPwI2yZZBpsQXOzYMA==[/tex] 之间的弧段 
  • 由[tex=5.143x3.357]fnpmC2J6JmQBLyo5NmGAz4YMSUI/hZpVsWqUQC5mevKxK/kjVp4JIu9uG8p+q3X0Jxnp9snz+/kjrnPOeN7T4DTHse7fMsGotGth9+Z3mSs=[/tex]得曲线的参数方程为 [tex=5.5x6.357]fnpmC2J6JmQBLyo5NmGAz5DZa5VbLkvqO1PJLWNSEP2C1Cvlr1puIXo6sEHfqtpf+boK0Fb2EsW1zoeI/6QyYxxLdva2+4nggm+RVxcMBaUZ9u3vgC673GCe/dYIbW/q[/tex][tex=3.714x1.357]23x/zo3NcLCxh1ZqEn8yRunMwNUMiSh1CAdyoRCsG7Y=[/tex]又[tex=19.429x2.857]CVRKMW8iCFRhCmUYmgSSTCgnNOSB2kLmuBZTOop1uuc4H/MRtU7+tqJt41zI9CaYMB1asbUcm+mfwkWmgr7jktrRVKXFajz3WwqxS5o4mlkwdyyP0sefANXdqEeEEcNRd6ysRHNqGbFr1KjDKGJTFA==[/tex] 故所求的弧长为 [tex=23.714x2.857]hyKbL89PSvMICDaovs6WGdJvzadq9nc+RXLEOEODd19p11Xky7aK9dkAWb2FNhkcj4B9hEjxmyf0suGruLMdRWs5Vam8PUF/nlj3qysdOLZB9laaUdImll0e+Hsaxy7m8sXtiSVeg7LtfFyDSmWycNPWmZqlU0hvFdoNQbhf28U=[/tex]

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    • 0

      以下程序的输出结果是() main( ) { int i , x[3][3]={9 , 8 , 7 , 6 , 5 , 4 , 3 , 2 , 1} , *p=&x[1][1] ; for(i=0 ; i<4 ; i+=2) printf("%d " , p[i]) ;

    • 1

      已知4x-3y-3z=0,x-3y+z=0(x≠0,y≠0,z≠0),那么x:y:z A: 4:3:9 B: 4:3:7 C: 12:7:9 D: 以上结论都不对

    • 2

      【单选题】请用地点定桩法在4分钟内记忆数字。 4 0 1 3 6 3 5 1 9 8 8 9 7 2 9 3 0 9 5 3 1 7 7 5 2 3 3 0 5 0 1 4 1 3 8 3 5 7 9 7 (5.0分) A. 已背 B. 未背

    • 3

      以下创建数组的方式错误的是() A: shortx[];x={1,2,3,4,5,6}; B: shortx[]=newshort[6];x[0]=9;x[1]=8;x[2]=7;x[3]=6;x[4]=5;x[5]=4; C: shortx[]=newshort[6];intlen=x.length;for(inti=0;i

    • 4

      【单选题】Which of the following matrices does not have the same determinant of matrix B: [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -1, 0, -9,-5] A. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 0; -1, 0, -9, -5] B. [1, 3, 0, 2; -2, -5, 7, 4; 1, 0, 9, 5; -1, 0, -9, -5] C. [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -3, -5, -2, -1] D. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 1; -1, 0, -9, -5]