如何用Maltab求解 y'(t) = 2*t , y(0) = 0?
举一反三
- 下列Matlab代码，能求解微分方程 y'(t) = 2*t , y(0) = 1的是( ) A: tspan = [0 5];<br> y0 = 0;<br> [t,y] = ode45(@(t,y) 2*t, tspan, y0); B: tspan = [0 5];<br>y0 = 1;<br>[t,y] = ode45(@(t,y) 2*t, tspan, y0); C: tspan = [0 5];<br>y0 = 1;<br>[t,y] = ode45(@(t,y) 2*y, tspan, y0); D: tspan = [0 5];<br>y0 = 1;<br>[t,y] = ode45(@(t,y) 2*t*y, tspan, y0);
- 如下命令中不能实现如下微分方程组[img=327x203]17e443a5d83ce02.png[/img]，在初值条件[img=172x112]17e443a5e2ead01.png[/img]下的特解求解的是： A: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0', 't') B: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1, y(0)=0', 't') C: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0') D: [x,y] = dsolve('Dx+5*x+y = exp(t)', 'Dy-x-3*y=0', 'x(0)=1', 'y(0)=0', 'x')
- 以下哪一项属于二阶齐次线性差分方程？ A: y(t+2)-3*y(t+1)+y(t)=0 B: y(t+2)-3*y(t+1)+y(t)=2 C: (y(t+2))^2-3*y(t+1)+y(t)=0 D: y(t+1)+3*y(t)=0
- 【计算题】描述某系统的微分方程为 y”(t) + 5y’(t) + 6y(t) = f(t) 求 当 f(t) = 2e-t , t ≥ 0 ; y(0)=2 , y ’ (0)= -1 时的全解; (10.0分)
- 已知X=1,Y=2,T=0 经程序段X=T:T=Y:Y=T 赋值后 X,Y 值分别为（）