[color=#000000]试求下列函数的[tex=0.5x0.786]gdMkE6SnyZedYLxpUxdkaQ==[/tex]变换：[/color][tex=3.429x1.357]rfOglxY4yMPIRekUZ7VeHA==[/tex]
举一反三
- [color=#000000]一质点作谐振[/color][color=#000000]动 [/color][color=#000000]，[/color][color=#000000]频[/color][color=#000000]率为[/color][tex=0.5x0.786]Ov81hmuvmfMhngaKtMBcFQ==[/tex][color=#000000]，[/color][color=#000000]则[/color][color=#000000]其[/color][color=#000000]振[/color][color=#000000]动动能变[/color][color=#000000]化[/color][color=#000000]频[/color][color=#000000]率[/color][color=#000000]为[/color][color=#000000]（[/color][color=#000000] [/color][color=#000000]）[/color] 未知类型：{'options': ['[tex=1.429x2.357]w/uX29w8QiV7wl7CApOqBepRKvCnwL0gPxiuiHWV69s=[/tex]', '[tex=1.429x2.357]Sj8Y4rwDiLPs1yv/BxJfglqdn1NDjvzXsyOYtffjU8Y=[/tex]', '[tex=0.5x0.786]dCrI67AYQK6jFSlsbBXzAg==[/tex]', '[tex=1.0x1.0]VNhhwWpOCbOxgVOS+hUMPQ==[/tex]', '[tex=1.0x1.0]d+RdgJ6f1xzS6Hn406qz3g==[/tex]'], 'type': 102}
- [color=#000000]试用[tex=0.5x0.786]gdMkE6SnyZedYLxpUxdkaQ==[/tex]变换法求解下列差分方程：[/color][color=#000000][/color](1)[tex=15.786x1.357]/oS6mIRz1WHFFxOcFWnqrF87laXN+7UrxSHwUepUafoE9A5t1/e6akiuZEvefqeL[/tex],[tex=10.714x1.357]+KTQovfPW2g/OioS6lF7Y/JSaQdsNTbmOZj0Za11XOaWgpugA0WZTO15PX+j2xMQ[/tex][tex=15.714x1.357]gkZCvoZhepAyayIzamkhvqLvjpjnbLG19MyhNkJqcPoGFzZZ2xZtDSNAt+JTQBDH[/tex],(2) [tex=16.643x1.357]xCNjqTMxh8REqfCdiBywePkG9h+XsFGwFNwnjimxwtybUP/JziKeI34w/2jSFTPE[/tex][tex=19.071x1.357]oSHVlzmZCRE9IMVaSB/QJxvyjyN3Xocbmiol02uPRA3syMWfEiA0wZVO85YtEKYV[/tex][tex=8.929x1.357]wiV1KNUnb57uDWXQR+IqQJXAp1tM5VqM9f3Z0pPrpiQ=[/tex](4) [tex=16.071x2.357]KYvGCyiB9w2958DPgB4riznRYdm3SbTduTCYZYbul6u8TVB04tYx9CNSobZyTzUG[/tex][tex=5.5x1.357]+zoBHsFCiBUrdx5xR9xdzA==[/tex]将[tex=15.786x1.357]/oS6mIRz1WHFFxOcFWnqrF87laXN+7UrxSHwUepUafoE9A5t1/e6akiuZEvefqeL[/tex]
- [color=#000000]试确定下列函数的终值：[/color][tex=9.786x2.786]+s1GKcmMwuL99rk5AxOjnDbwxWNkgvIIP0dkLoTXdPbgKVxWv0d6zlQumsw0xodq[/tex]
- 求下列[tex=0.5x0.786]gdMkE6SnyZedYLxpUxdkaQ==[/tex]函数的反变换（[tex=2.357x1.0]7uYv/Vl6CBg9JTOroBoExw==[/tex]）。[tex=8.071x2.429]b5mSSTuf0rlXnj3vtPVYILfQMMTGikwJnvvxTfsaooVVybq0pfd6S9atoV7pP+XdBtoh3j+YnUO+q7Llede9pA==[/tex]
- [color=#000000]试用叠加法求下列各梁中截面 [/color][color=#000000][tex=0.786x1.0]Yn3GgEZev6SOu2r4v1WnCw==[/tex] [/color][color=#000000]的挠度和截面 [/color][color=#000000][tex=0.786x1.0]ri6gmnf1+J9dGqG5/1sV6A==[/tex] [/color][color=#000000]的转角。图中[tex=0.5x1.0]O7oCSJ9lkssShf7eQ8zpFA==[/tex] 、 [tex=0.357x1.0]5vVfAZliYwqMw8JaLE+iEA==[/tex]、 [tex=0.571x0.786]c59+3vo0/Vn/FvNRhDRu5g==[/tex][color=#000000]、[/color][tex=1.214x1.0]t0L224Rql2wXlvNxHSmWkg==[/tex][color=#000000]等为[/color][color=#000000]已知。[/color][/color][color=#000000][color=#000000][img=542x302]17a982afc025286.png[/img][/color][/color]