证明下列等式：[tex=13.786x2.786]TsAUIF3pWh7cpiVYYTU26WQE7BFTclN/9PjylzA54zsAiTF++YdnfUt3tSp+OZxQsZORSIHYK1mTrEVJfQHHA/i59+042eK/PqW+XkfrWU0=[/tex]([tex=0.643x0.786]35ReWWGs/YPu3n9y5K5w7g==[/tex]是正整数)。
解：被积函数正是[tex=3.571x1.429]1h1bfecshSHFWauPdL6NII0mwb441tv7kJ8lndzSnrFIHMgNOMaSflicIsAY7NPaHBUVmCarufvXjtE0/HoYgw==[/tex]的实部，故积分为[tex=24.5x2.786]uoiQdCKSAwgdbSYSLlxGpne2q+oxiiIQtWwGwxOmgNAWbIhJh8M9M2Xw/1tYWQaStJCATqAyZ6EnjuNmA0DhwFypBtQQ1EHoaEwPueXgPfeUZR0Fq/ZpMGvmXZqlhzZd1Y1Lvy/qGDErF6kguW+19KiJ2+pwJohZAh5jgOyCTWaoVcAVzY0S5Yv+oR2qVwlrWzbi54jz5dTGZ8IL8hCwIOaRuKldwRo1lC3HOz9WUTME9btFObmWp/2TvwfYMXQv[/tex][tex=39.286x3.357]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[/tex][tex=21.214x4.071]Rpiq70W6rZe8hLsHd+w7/a4lylCwUtOb2q8zSs8SV72Gt1Cm2loJPMv6UCMmanpH8VCdLHwP7P6BxtSMtroLk8WW1hWpDdW8P0frP4r41lKdGeyoR0Hwh09cxzr1DiTR0lwIf1p20129bjmHjQa0koVBtobLhy5tcFwnXI6c08MrsPA5bLYmDYPI52W4sODtDc6z2hhn9wkcUYyjmNuSnC6LCPZ9Kxv5ucvfXVVVHP43DqBGfpfU6Inx6Kx5Ep7xgTfBxeJuJT8T9QdMdcXzlQ==[/tex]
举一反三
- set1 = {x for x in range(10) if x%2!=0} print(set1) 以上代码的运行结果为？ A: {1, 3, 5, 7, 9} B: {1, 3, 5, 7} C: {3, 5, 7, 9} D: {3, 5, 7}
- set1 = {x for x in range(10) if x%2!=0} set1.remove(1) print(set1) 以上代码的运行结果为？ A: {1, 3, 5, 7, 9} B: {1, 3, 5, 7} C: {3, 5, 7, 9} D: {3, 5, 7}
- 证明:方程[tex=5.429x1.214]unY/GxrtAwP+9oZ/4P89yQ==[/tex]([tex=0.643x0.786]35ReWWGs/YPu3n9y5K5w7g==[/tex]为正整数,[tex=1.429x1.0]EHzsglf5n1gYY95L4Z4giQ==[/tex]为实数),当[tex=0.643x0.786]35ReWWGs/YPu3n9y5K5w7g==[/tex]为偶数时至多有两个实根,当 [tex=0.643x0.786]35ReWWGs/YPu3n9y5K5w7g==[/tex]为奇数时至多有三个实根.[br][/br][br][/br]
- 以下程序段实现的输出是（）。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9
- 【单选题】下面程序段的输出结果是 () 。 int k,a[3][3]={1,2,3,4,5,6,7,8,9}; for (k=0;k<3;k++) printf(“%d”,a[k][2-k]); ( A ) 3 5 7 ( B ) 3 6 9 ( C ) 1 5 9 ( D ) 1 4 7 A. 3 5 7 B. 3 6 9 C. 1 5 9 D. ( A ) 1 4 7
内容
- 0
下列哪条语句是正确的（ ） A: A=[1 2;3 4];B=[3;7];A.*B; B: A=cell(2,3);A(1,2)=[4;5]; C: A=[2 3 5 7;9 4 6 1;7 3 2 5];B=[1 7;0 5];A(2:end,2:2:end) D: x=-5:5;y=-5:5;z=x.*x-y.*y;surf(x,y,z);
- 1
【单选题】请用地点定桩法在4分钟内记忆数字。 4 0 1 3 6 3 5 1 9 8 8 9 7 2 9 3 0 9 5 3 1 7 7 5 2 3 3 0 5 0 1 4 1 3 8 3 5 7 9 7 (5.0分) A. 已背 B. 未背
- 2
已知列表x=[3, 5, 6, 7, 9]，那么x[::-1]的结果是 A: [3, 9] B: [3, 5, 6, 7, 9] C: [3, 5, 6, 7] D: [9, 7, 6, 5, 3]
- 3
5-1，对于下列代码，输入是1 3 5 7 9，那么 a 的值是什么？a = input().split() A: 1 B: 1 3 5 7 9 C: [1, 3, 5, 7, 9] D: ['1', '3', '5', '7', '9']
- 4
【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=