• 2022-05-27
    设方阵[tex=0.929x1.0]FV0k2T/xaj6dPCbFnkB3/g==[/tex]满足[tex=7.214x1.357]317mMb/UfJBjZHDU7raSnvWERkZyfhOwPTdoUD2f01twirl+C39n2DOIdvf2c+0M1GvW6bVLWq82kqUyfYOSVw==[/tex],证明[tex=0.929x1.0]FV0k2T/xaj6dPCbFnkB3/g==[/tex]的特征值只能取1或2.
  • 举一反三